Generating Permutations of Digits 1-4 in Python Without Repetition
Given the digits 1, 2, 3, and 4, how many distinct three-digit numbers can be formed without repeating any digit? This is a classic combinatorial problem equivalent to calculating permutations of 4 items taken 3 at a time, denoted as P(4,3) = 4! / (4-3)! = 24. Brute-force Approach with Nested Loops...