Optimizing Integer Factorization with Logarithmic Comparison for Minimal Product
Given an integer n, the task is to find the smallest positive integer N such that the number of divisors of N equals n. This problem leverages the divisor count formula: if N = ∏ p_i^{k_i}, then the number of divisors is ∏ (k_i + 1). Thus, n = ∏ (k_i + 1), where k_i are non-negative integers. A naiv...