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Understanding Copy Constructor Elision and Return Value Optimization in C++

Tech May 8 4

During copy initialization (using the equals sign), compilers may bypass copy or move constructors and create objects directly. This optimizatino is permitted but not required by the standard.

std::string book_id = "123";
// Can be rewritten as:
std::string book_id("123");

In this case, the compiler might skip creating a temporary string object and copying it, instead constructing the object directly.

Consider this example demonstrating Return Value Optimization (RVO):

class Employee {
public:
    Employee() {
        std::cout << "Default constructor at " << this << std::endl;
    }
    
    Employee(const Employee& e) {
        std::cout << "Copy constructor at " << this << std::endl;
    }
    
    ~Employee() {
        std::cout << "Destructor at " << this << std::endl;
    }
};

Employee createEmployee() {
    Employee emp;
    return emp;
}

void demo() {
    Employee e = createEmployee();
}

When executed, only the default constructor and destructor calls appear, showing the compiler optimized away both:

  1. The temporary object creation during return
  2. The copy construction during initialization

Another case where copy construction occurs is during pass-by-value:

void processEmployee(Employee e) {
    // Function body
}

int main() {
    Employee emp;
    processEmployee(emp);  // Copy constructor invoked here
    return 0;
}

This demonstrates mandatory copy construction when passing objects by value, unlike the optimizable cases shown earlier.

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