When processing identification strings composed of uppercase letters, a common pattern involves converting characters to numerical values and aggregating them through multiplication. Consider a scenario where two entities—a celestial object and a team—must be matched based on their respective name encodings.

Each character maps to its 1-indexed position in the alphabet (A→1, B→2, ..., Z→26). For a given string, compute the cumulative product of these mappnigs. The matching criterion requires comparing the remainders when dividing these products by 47. If congruent, the system indicates readiness; otherwise, it signals a wait state.

Input Specification Two whitespace-separated strings, each containing 1 to 6 uppercase English letters. The first represents the comet identifier; the second represents the team identifier.

Algorithmic Approach

1. Initialize accumulators for both identifiers to multiplicative identity (1).
2. For each character in the first string, convert to its ordinal value and multiply into the first accumulator.
3. Repeat for the second string, populating the second accumulator.
4. Reduce both values modulo 47 and compare equality.
5. Output "GO" for matching remainders, "STAY" otherwise.

Implementation Considerations Since 26^6 exceeds 32-bit integer capacity (308,915,776), 64-bit integers prevent overflow during intermediate calculations. Alternatively, apply the modulo operation during each multiplication step to maintain numerical bounds throughout computation.

#include <bits/stdc++.h>
using namespace std;

int computeSignature(const string& identifier) {
    const int MODULUS = 47;
    long long accumulator = 1;
    for (char symbol : identifier) {
        int value = symbol - 'A' + 1;
        accumulator = (accumulator * value) % MODULUS;
    }
    return static_cast<int>(accumulator);
}

int main() {
    string celestialBody, squad;
    cin >> celestialBody >> squad;
    
    int cometHash = computeSignature(celestialBody);
    int teamHash = computeSignature(squad);
    
    cout << (cometHash == teamHash ? "GO" : "STAY") << endl;
    return 0;
}